Download Differential Geometry: Theory and Applications by Philippe G. Ciarlet PDF

By Philippe G. Ciarlet

This ebook provides the fundamental notions of differential geometry, similar to the metric tensor, the Riemann curvature tensor, the elemental sorts of a floor, covariant derivatives, and the elemental theorem of floor concept in a self-contained and available demeanour. even supposing the sector is usually thought of a classical one, it has lately been rejuvenated, because of the manifold purposes the place it performs an important position.

The ebook offers a few very important purposes to shells, akin to the speculation of linearly and nonlinearly elastic shells, the implementation of numerical equipment for shells, and mesh iteration in finite aspect tools.

This quantity could be very precious to graduate scholars and researchers in natural and utilized arithmetic.

Contents: An advent to Differential Geometry in three (P G Ciarlet); An advent to Shell idea (P G Ciarlet & C Mardare); a few New effects and present demanding situations within the Finite aspect research of Shells (D Chapelle); A Differential Geometry method of Mesh iteration (P Frey).

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Example text

Proof. We follow the argument in [MIS]. Let 0 < r < 1. On the disk D(0, r) define the metric r ρr (z) = 2 . r − z2 Then straightforward calculations (or change of variable) show that ρr is the analogue of the Poincar´e metric for D(0, r): it has constant curvature −4 and is invariant under conformal maps. Define v= f ∗σ . ρr Observe that v is continuous and nonnegative on D(0, r) and that v → 0 ¯ r) ⊂⊂ D while ρr → ∞). when |z| → r (since f ∗ σ is bounded above on D(0, It follows that v attains a maximum value M at some point τ ∈ D(0, r).

Then on U we have Δ log(|f |2 ) = Δ log f + log f ∂ ∂ ∂ ∂ log f + 4 log f = 4 ∂z ∂z ∂z ∂z = 0. Of course the reader may also check that log f is harmonic. We conclude this section with some exercises for the reader. Exercises 1. Calculate that, for a > 0, ∂2 log 1 + (zz)a ∂z∂z = a2 (zz)a−1 . (1 + (zz)a )2 2. If g is holomorphic (and f continuously differentiable), then calculate that (f ◦ g) = ( f ◦ g) · |g |2 . 3. If f is holomorphic (and g continuously differentiable), then calculate that (f ◦ g) = (f ◦ g) g + (f ◦ g)[(Dx g)2 + (Dy g)2 ] .

Proof. First suppose that f (0) = 0. For R > 0 let CR be the set of points in D that have Poincar´e distance R from 0. Since the Poincar´e metric is invariant under rotations (after all, rotations are holomorphic self-maps), it follows that CR is a Euclidean circle (however, this circle will have Euclidean radius (e2R − 1)/(e2R + 1), not R). Since f (0) = 0 and f preserves the metric, it follows that f (CR ) = CR . The fact that f is distance-preserving then shows that f is one-to-one on each CR .

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